• Some hours of hard work to find a workaround for this issue...I hope that it will help some of you
    as this simple issue should be quite common.

    Here is a sample xml that reveal the issue (sample.xml):

       1: <?xml version="1.0" encoding="UTF-8"?>
       2: <address xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       3:         xmlns="http://www.example.com/test"
       4:         xsi:schemaLocation="http://www.example.com/test sample.xsd">
       5:   <name>name</name>
       6:   <street>street</street>
       7:   <city>city</city>
       8:   <country>country</country>
       9: </address>

    A very simple XSD schema (sample.xsd)

       1: <?xml version="1.0" encoding="UTF-8" standalone="no"?>
       2: <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
       3:            targetNamespace="http://www.example.com/test"
       4:            xmlns="http://www.example.com/test">
       5:     <xs:element name="address">
       6:         <xs:complexType>
       7:             <xs:sequence>
       8:                 <xs:element name="name" type="xs:string" />
       9:                 <xs:element name="street" type="xs:string" />
      10:                 <xs:element name="city" type="xs:string" />
      11:                 <xs:element name="country" type="xs:string" />
      12:             </xs:sequence>
      13:         </xs:complexType>
      14:     </xs:element>
      15: </xs:schema>

    And a simple java client, using JUNIT4

       1: import java.io.InputStream;
       2: &160;
       3: import javax.xml.parsers.DocumentBuilder;
       4: import javax.xml.parsers.DocumentBuilderFactory;
       5: &160;
       6: import org.apache.commons.jxpath.JXPathContext;
       7: import org.junit.Assert;
       8: import org.junit.Test;
       9: import org.w3c.dom.Document;
      10: &160;
      11: public class JXpath12NameSpaceIssue{
      12: &160;
      13:   @Test
      14:   public void testCountNonWorkingXML() {
      15:     InputStream xmlStream = this.getClass().getResourceAsStream("/sample.xml");
      16: &160;
      17:     try {
      18:       JXPathContext context = this.getJXPathContext(xmlStream);
      19:       Double value = (Double)context.getValue("count(//name)");
      20:       Assert.assertEquals(1, value, 0.0);
      21:     } catch (Exception e) {
      22:       Assert.fail(e.getMessage());
      23:     }
      24:   }
      25: &160;
      26:   public JXPathContext getJXPathContext(InputStream inputStream) {
      27:     try {
      28:       DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
      29:       factory.setValidating(false); //This is for xml with DTD only!
      30:       factory.setNamespaceAware(true); //if namespace in xml, make no difference if true or false
      31:       factory.setFeature("http://apache.org/xml/features/validation/schema", true);
      32: &160;
      33:       DocumentBuilder builder = factory.newDocumentBuilder();
      34:       builder.setErrorHandler(new JXPathErrorHandler());
      35: &160;
      36:       Document document = builder.parse(inputStream);
      37:       JXPathContext context = JXPathContext.newContext(document);
      38: &160;
      39:       context.setLenient(true);
      40:       return context;
      41:     } catch (Throwable throwable) {
      42:       throwable.printStackTrace();
      43:     }
      44:     return null;
      45:   }


    This line Double value = (Double)context.getValue("count(//name)"); will always make the
    test case fail, as the value of context.getValue("count(//name)");&160; is 0.0 instead of 1.0

    As soon as You remove the namespace from the XML file

       1: <?xml version="1.0" encoding="UTF-8"?>
       2: <address xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       3:         xmlns="http://www.example.com/test"
       4:         xsi:schemaLocation="http://www.example.com/test sample.xsd">


    The code will return the correct value aka 1.0. The explanation has been found on internet thanks to Google

    From http://www.mail-archive.com/This email address is being protected from spambots. You need JavaScript enabled to view it./msg07865.html

    JXPath 1.2 handles namespaces somewhat differently from JXPath 1.1. It
    is following the XPath specification more closely. The specification
    describes the procedure of matching a name by comparing so-called
    expanded names. An expanded name is a combination of a local name and a
    namespace URI. In Quote from the spec: "Two expanded-names are equal if
    they have the same local part, and either both have a null namespace
    URI or both have non-null namespace URIs that are equal." The notion of
    default namespace applies to elements of an XML document, but does not
    apply to XPaths. Quote: "if the QName does not have a prefix, then the
    namespace URI is null (this is the same way attribute names are
    expanded). It is an error if the QName has a prefix for which there is
    no namespace declaration in the expression context

    To remedy the situation, do the following two things:

    1. Register the namespace with the JXPathContext:
    context.registerNamespace("schema", http://www.verticon.com/react2/schema;);

    Namespaces do not apply to objects, unless, of course, those objects are handled by
    custom NodePointers that are made namespace-aware.&160; The standard distribution of
    JXPath does not contain any such NodePointers. As far as the interpretation of XPaths
    on XML documents is concerned, we are bound by the XPath 1.0 standard.&160;
    On the other hand, the standard does not say anything about applying XPaths to any
    non-XML object models, therefore we were free to make pretty much arbitrary choices.&160;
    One of those choices was to ignore namespaces.

    More can also be read here

    When using namespaces, it is important to remember that XPath matches qualified
    names (QNames) based on the namespace URI, not on the prefix. Therefore the XPath
    "//foo:bar" may not find a node named "foo:bar" if the prefix "foo" in the context
    of the node and in the execution context of the XPath are mapped to different URIs.
    Conversely, "//foo:bar" will find the node named "biz:bar", if "foo" in the
    execution context and "biz" in the node context are mapped to the same URI.

    In order to use a namespace prefix with JXPath, that prefix should be known to
    JXPathContext. JXPathContext knows about namespace prefixes declared on the
    document element of the context node (the one passed to
    JXPathContext.newContext(node)), as well as the ones explicitly registered using
    the JXPathContext.registerNamespace(prefix, namespaceURI) method.

    So you should end up with:

       1: Document document = builder.parse(inputStream);
       2: JXPathContext context = JXPathContext.newContext(document);
       3: context.registerNamespace("schema", "http://www.example.com/test");
       4: Double value = (Double)context.getValue("count(//schema:name)");

    You can also go another way, and remove any namespace by forcing JAXB2 to
    create XML and DOM without qualified namespace

    In&160; com.example.xml.jaxb.package-info.java.package-info.java go from

    to&160; XmlNsForm.UNQUALIFIED

       1: @javax.xml.bind.annotation.XmlSchema
       2: (namespace = "http://www.example.com/test",
       3: elementFormDefault = javax.xml.bind.annotation.XmlNsForm.UNQUALIFIED)
       4: package com.example.test;